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(C)=3C^2-30C+200
We move all terms to the left:
(C)-(3C^2-30C+200)=0
We get rid of parentheses
-3C^2+C+30C-200=0
We add all the numbers together, and all the variables
-3C^2+31C-200=0
a = -3; b = 31; c = -200;
Δ = b2-4ac
Δ = 312-4·(-3)·(-200)
Δ = -1439
Delta is less than zero, so there is no solution for the equation
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